In the circuit shown in fig. E 1 = 3 volt, E 2 = 2 volt, E 3 = 1 volt and R = r 1 = r 2 = r 3 = 1 ohm.
(i) Find potential difference in Volt between the points A and B with A & B unconnected.
(ii) If r 2 is short circuited and the point A is connected to point B through a zero resistance wire, find the current through R in ampere.

Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
[(i) 2 volt, (ii) 2A]
Sol. (i)


V AB = 2V
⇒ i 2 = 0 & i 1 = i 3
2 = 3 – i, r,
⇒ i 1 = 1A
⇒ i 3 = 1A
(ii)

Apply kvl in ABCD;
2 – (I 1 + I 2 + I 3 )R = 0
I 1 + I 2 + I 3 = 2
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